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Tinku Tara June 4, 2023 None 0 Comments

Question Number 169809 by mokys last updated on 09/May/22

prove that ∫_0 ^( ∞) x^r . e^(ax) dx = (−a)^(−r−1) .Γ(r+1)

$${prove}\:{that}\:\int_{\mathrm{0}} ^{\:\infty} {x}^{{r}} \:.\:{e}^{{ax}} \:{dx}\:=\:\left(−{a}\right)^{−{r}−\mathrm{1}} \:.\Gamma\left({r}+\mathrm{1}\right) \\ $$

Commented by mokys last updated on 09/May/22

$$????? \\ $$

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