Question Number 191187 by mathlove last updated on 20/Apr/23
$${prove}\:{that} \\ $$$$\mathrm{1}:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−{tanx}}{{x}^{\mathrm{3}} }=\frac{−\mathrm{1}}{\mathrm{3}} \\ $$$$\mathrm{2}:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−{tan}^{−\mathrm{1}} {x}}{{x}^{\mathrm{3}} }=\frac{\mathrm{1}}{\mathrm{3}} \\ $$
Commented by mathlove last updated on 23/Apr/23
$${solve}\:{this} \\ $$