Menu Close

Prove-that-1-sin-2-sec-2-1-




Question Number 106609 by DeepakMahato last updated on 06/Aug/20
Prove that  (1−sin^2 θ)sec^2 θ=1
Provethat(1sin2θ)sec2θ=1
Commented by mohammad17 last updated on 06/Aug/20
when:1−sin^2 θ=cos^2 θ  when:sec^2 θ=(1/(cos^2 θ))    ⌋(1−sin^2 θ)sec^2 θ=cos^2 θ×(1/(cos^2 θ))=1       m.ss.mohammad
when:1sin2θ=cos2θwhen:sec2θ=1cos2θ(1sin2θ)sec2θ=cos2θ×1cos2θ=1m.ss.mohammad
Answered by JDamian last updated on 06/Aug/20
(1−(1−cos^2 θ))(1/(cos^2 θ))=cos^2 θ (1/(cos^2 θ)) = 1
(1(1cos2θ))1cos2θ=cos2θ1cos2θ=1

Leave a Reply

Your email address will not be published. Required fields are marked *