prove-that-1-sinx-sinxcosx-tanx-cotx-secx-hence-differentiate-the-function-

Question Number 129051 by oustmuchiya@gmail.com last updated on 12/Jan/21

p r o v e t h a t \frac{1 + s i n x}{s i n x c o s x} =

t a n x + c o t x + s e c x h e n c e

d i f f e r e n t i a t e t h e f u n c t i o n

Answered by mindispower last updated on 12/Jan/21

1 = {c o s}^{2} (x) + {s i n}^{2} (x)

\Leftrightarrow \frac{{c o s}^{2} (x) + {s i n}^{2} (x) + s i n (x)}{c o s (x) s i n (x)}

= \frac{c o s (x)}{s i n (x)} + \frac{s i n x)}{c o s (x)} + \frac{1}{c o s (x)}

= c o t (x) + t a n (x) + s e c (x)