Question Number 43550 by peter frank last updated on 11/Sep/18
$${prove}\:{that} \\ $$$$\int_{\:} \:\mathrm{4}_{\:\:\:\:\:} ^{\mathrm{4}^{\mathrm{4}^{{x}} } } .\mathrm{4}^{\mathrm{4}^{{x}} } .\mathrm{4}^{{x}} {dx}=\frac{\mathrm{4}^{\mathrm{4}^{{x}} } }{\left(\mathrm{log}\:\underset{{e}} {\mathrm{4}}\right)} \\ $$
Commented by peter frank last updated on 15/Sep/18
$${help}\:{plz} \\ $$