prove-that-a-2-x-2-dx-x-2-a-2-x-2-a-2-2-sin-1-x-a-c- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 125837 by joki last updated on 14/Dec/20 provethat:∫a2−x2dx=x2a2−x2+a22sin−1(xa)+c Answered by Dwaipayan Shikari last updated on 14/Dec/20 Takex=asinθ,1=acosθdθdx∫a2−x2dx=∫acosθa2−a2sin2θdθ=a2∫cos2θdθ=a22∫1+cos2θdθ=a2θ2+a24sin2θ+Cθ=sin−1xasin2θ=2xa2a−x2So∫a2−x2dx=a2sin−1xa2+x2a2−x2+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 4sin-2pi-7-sec-pi-14-cot-pi-7-Next Next post: Question-60303 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.