Prove-that-a-A-A-B-A-c-A-B-A-B-A-b-A-A-B-A-d-A-A-B-A-B-

Question Number 96811 by Ar Brandon last updated on 05/Jun/20

Prove that;

a ∖ A + A \cdot B = A c ∖ (A + B^{}) \cdot (A + \bar{B}) = A

b ∖ A \cdot (A + B) = A d ∖ A + \bar{A B} = A + B

Answered by 1549442205 last updated on 05/Jun/20

your symbol {isn}^{'} t normal : what does A . B means ? A \cap B ? A + B = A \cup B ?

Commented by Ar Brandon last updated on 05/Jun/20

It has to do with logic gates.