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Question Number 104894 by bramlex last updated on 24/Jul/20
prove that cos^6 a −sin^6 a =   cos 2a (1−(1/4)sin^2 2a)
provethatcos6asin6a=cos2a(114sin22a)
Answered by john santu last updated on 24/Jul/20
(1)cos^6 a−sin^6 a = (cos^2 a−sin^2 a)  (cos^4 a+sin^2 a cos^2 a+sin^4 a)  =(cos^2 a−sin^2 a){(cos^2 a+sin^2 a)^2 −(1/4)(2sin a cos a)^2 }  = cos 2a {1−(1/4)sin 2a } (JS ⊛)
(1)cos6asin6a=(cos2asin2a)(cos4a+sin2acos2a+sin4a)=(cos2asin2a){(cos2a+sin2a)214(2sinacosa)2}=cos2a{114sin2a}(JS)

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