prove-that-cos-6-a-sin-6-a-cos-2a-1-1-4-sin-2-2a- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 104894 by bramlex last updated on 24/Jul/20 provethatcos6a−sin6a=cos2a(1−14sin22a) Answered by john santu last updated on 24/Jul/20 (1)cos6a−sin6a=(cos2a−sin2a)(cos4a+sin2acos2a+sin4a)=(cos2a−sin2a){(cos2a+sin2a)2−14(2sinacosa)2}=cos2a{1−14sin2a}(JS⊛) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-decompose-the-fraction-F-x-1-x-3-x-1-4-2-find-the-sumA-n-1-1-n-3-n-1-4-and-B-n-1-1-n-n-3-n-1-4-3-what-is-the-value-of-n-0-1-n-1-Next Next post: lim-x-0-cos-sin-x-cos-x-x-4- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.