Prove-that-e-ipi-1-0-

Question Number 29049 by NECx last updated on 03/Feb/18

P r o v e t h a t

e^{i π} + 1 = 0

Answered by Penguin last updated on 03/Feb/18

e^{i θ} = \cos (θ) + i \sin (θ)

θ = π

∴ e^{i π} = - 1 + i (0)

= - 1

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