prove-that-e-ipi-1-0-

Question Number 33496 by malwaan last updated on 17/Apr/18

prove that

e^{i π} + 1 = 0

Answered by MJS last updated on 17/Apr/18

just use the definition of z \in C :

z = r e^{φ i} = r \cos (φ) + r \sin (φ) i \Rightarrow

\Rightarrow e^{π i} = 1 \cos (π) + 1 \sin (π) i =

= - 1 + 0 i = - 1

- 1 + 1 = 0

Commented by malwaan last updated on 18/Apr/18

thank you so much

Facebook Tweet Pin