Question Number 181039 by depressiveshrek last updated on 20/Nov/22
$${Prove}\:{that}\:{for}\:{all}\:{a}^{\mathrm{2}} \:{divisible}\:{by}\:{b}, \\ $$$${a}\:{is}\:{also}\:{divisible}\:{by}\:{b} \\ $$$${for}\:{all}\:{a},\:{b}\:\in\:\mathbb{N} \\ $$
Commented by mr W last updated on 20/Nov/22
$${it}'{s}\:{not}\:{true}! \\ $$$${example}: \\ $$$$\mathrm{4}^{\mathrm{2}} \:{is}\:{divisible}\:{by}\:\mathrm{8}. \\ $$$${but}\:\mathrm{4}\:{is}\:{not}\:{divisible}\:{by}\:\mathrm{8}. \\ $$
Commented by depressiveshrek last updated on 20/Nov/22
$${what}\:{if}\:{a}>{b} \\ $$
Commented by Frix last updated on 20/Nov/22
$$\mathrm{what}\:\mathrm{about}\:{a}=\mathrm{21}\wedge{b}=\mathrm{9} \\ $$