Question Number 167977 by LEKOUMA last updated on 30/Mar/22
$${Prove}\:{that} \\ $$$${I}_{{n}} =\frac{\mathrm{1}}{\mathrm{2}^{{n}+\mathrm{1}} }\int_{\pi} ^{\mathrm{4}{n}\pi} {x}\mathrm{cos}\:\frac{{x}}{\mathrm{2}}{dx}=\frac{\mathrm{2}−\pi}{\mathrm{2}^{{np}} } \\ $$
Answered by mindispower last updated on 01/Apr/22
$${wher}\:{is}\:{p}? \\ $$