Question Number 186188 by aba last updated on 02/Feb/23
$$\mathrm{Prove}\:\mathrm{that}\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{p}} {\prod}}\mathrm{tan}\left(\frac{\mathrm{k}\pi}{\mathrm{2p}+\mathrm{1}}\right)=\sqrt{\mathrm{2p}+\mathrm{1}} \\ $$