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prove-that-n-3-n-lt-n-n-




Question Number 34678 by math khazana by abdo last updated on 09/May/18
prove that āˆ€ nā‰„3     (āˆšn)  <^n (āˆš(n!))
$${prove}\:{that}\:\forall\:{n}\geqslant\mathrm{3}\:\:\:\:\:\sqrt{{n}}\:\:<^{{n}} \sqrt{{n}!} \\ $$$$ \\ $$

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