Prove-that-tan-30-30-6-2-3-2-

Question Number 128333 by liberty last updated on 06/Jan/21

Prove that \tan 30 ° 30^{'} = \sqrt{6} + \sqrt{2} - \sqrt{3} - 2

Commented by MJS_new last updated on 06/Jan/21

not true ?!

\tan (7.5 ° + 180 ° \times n) = - 2 + \sqrt{2} - \sqrt{3} + \sqrt{6}

Commented by liberty last updated on 07/Jan/21

yes . i think it true for \tan 7 ° 30^{'}

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