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prove-that-x-5-e-x-2-sin-x-3-dx-0-25474-




Question Number 60631 by aliesam last updated on 23/May/19
prove that∫_(−∞) ^∞ x^5 e^(−x^2 ) sin(x^3 ) dx=0.25474
$$\mathrm{prove}\:\mathrm{that}\underset{−\infty} {\overset{\infty} {\int}}\mathrm{x}^{\mathrm{5}} \mathrm{e}^{−\mathrm{x}^{\mathrm{2}} } \mathrm{sin}\left(\mathrm{x}^{\mathrm{3}} \right)\:\mathrm{dx}=\mathrm{0}.\mathrm{25474} \\ $$

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