Q-0-x-c-c-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 156470 by puissant last updated on 11/Oct/21 Q=∫0∞xccxdx Answered by puissant last updated on 11/Oct/21 posonscx=eu⇒exlnc=eu⇒x=ulnc⇒dx=dulnc⇒Q=∫0∞(ulnc)ceu×dulnc=1(lnc)c+1∫0∞uceudu=1(lnc)c+1∫0∞uc−1+1e−udu∴∵Q=∫0∞xccxdx=Γ(c+1)(lnc)c+1..……….Lepuissant……… Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-90-Next Next post: soit-o-x-f-t-x-0-x-t-2-f-t-dt-determiner-f-1- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.