q-1-q-2-x-0-8-x-2-x-

Question Number 27334 by darkalestero1@gmail.com last updated on 05/Jan/18

\frac{q_{1}}{q_{2}} = {(\frac{x}{0.8 - x})}^{2}; x = ?

Answered by mrW1 last updated on 05/Jan/18

\frac{x}{0.8 - x} = \pm \sqrt{\frac{q_{1}}{q_{2}}}

\frac{0.8 - x}{x} = \pm \sqrt{\frac{q_{2}}{q_{1}}}

\frac{0.8}{x} = 1 \pm \sqrt{\frac{q_{2}}{q_{1}}}

\Rightarrow x = \frac{0.8}{1 \pm \sqrt{\frac{q_{2}}{q_{1}}}}

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