Question Number 129292 by AgnibhoMukhopadhyay last updated on 14/Jan/21
$$\mathrm{Q}\:\mathrm{129271}\:\mathrm{please}\:\mathrm{answer} \\ $$
Commented by prakash jain last updated on 14/Jan/21
$$\mathrm{I}\:\mathrm{get}\:−\mathrm{ve}\:\mathrm{answer}.\:\mathrm{check}\:\mathrm{original} \\ $$$$\mathrm{questions}\:\mathrm{comment}. \\ $$$$\mathrm{Maybe}\:\mathrm{somebody}\:\mathrm{else}\:\mathrm{can}\:\mathrm{comment} \\ $$
Answered by ajfour last updated on 14/Jan/21
Commented by ajfour last updated on 14/Jan/21
$$\frac{\left(\mathrm{5}+\mathrm{8}+\mathrm{9}\right){N}}{\mathrm{10}}−\mathrm{3}\left(\mathrm{160}\right)+\mathrm{2}\left(\mathrm{160}\right)=\mathrm{2}{N} \\ $$$$\Rightarrow\:\:\mathrm{22}{N}−\mathrm{1600}=\mathrm{20}{N} \\ $$$$\Rightarrow\:\:\mathrm{2}{N}=\mathrm{1600} \\ $$$$\Rightarrow\:\:\:\:\:\:\:{N}=\mathrm{800}\:. \\ $$
Commented by ajfour last updated on 14/Jan/21
Commented by MathSh last updated on 14/Jan/21
$${Thanks}\:{Sir} \\ $$