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Q-Find-the-minimum-value-of-3cosx-4sinx-8-




Question Number 81763 by Khyati last updated on 15/Feb/20
Q. Find the minimum value of   3cosx + 4sinx + 8.
Q.Findtheminimumvalueof3cosx+4sinx+8.
Commented by john santu last updated on 15/Feb/20
f(x)= 3cos x+4sin x+8  f(x) = (√(9+16)) cos (x−θ)+8 , where θ=tan^(−1) ((4/3))  f(x)= 5cos (x−θ)+8  minimum value is −5+8 = 3
f(x)=3cosx+4sinx+8f(x)=9+16cos(xθ)+8,whereθ=tan1(43)f(x)=5cos(xθ)+8minimumvalueis5+8=3
Commented by Khyati last updated on 16/Feb/20
Do you have any other method except  differentiation ??
Doyouhaveanyothermethodexceptdifferentiation??

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