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Question-100270




Question Number 100270 by Coronavirus last updated on 25/Jun/20
Answered by abdomsup last updated on 26/Jun/20
A_n =Σ_(k=n) ^(2n)  (π/k) =_(p=k−n) π Σ_(p=0) ^n  (1/(p+n))  =(π/n)Σ_(p=0) ^n  (1/(1+(p/n)))→π ∫_0 ^1  (dx/(1+x))  πln(2) ⇒lim_(n→+∞)  A_n =πln2
$${A}_{{n}} =\sum_{{k}={n}} ^{\mathrm{2}{n}} \:\frac{\pi}{{k}}\:=_{{p}={k}−{n}} \pi\:\sum_{{p}=\mathrm{0}} ^{{n}} \:\frac{\mathrm{1}}{{p}+{n}} \\ $$$$=\frac{\pi}{{n}}\sum_{{p}=\mathrm{0}} ^{{n}} \:\frac{\mathrm{1}}{\mathrm{1}+\frac{{p}}{{n}}}\rightarrow\pi\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{dx}}{\mathrm{1}+{x}} \\ $$$$\pi{ln}\left(\mathrm{2}\right)\:\Rightarrow{lim}_{{n}\rightarrow+\infty} \:{A}_{{n}} =\pi{ln}\mathrm{2} \\ $$
Commented by Ar Brandon last updated on 26/Jun/20
cool Mr mathmax��
Answered by DGmichael last updated on 26/Jun/20
Commented by Ar Brandon last updated on 26/Jun/20
�� C'est cool DG, même comme c'est pas tout à fait ce qu'il...����
Commented by DGmichael last updated on 26/Jun/20
quelle était donc sa question ??
Commented by Ar Brandon last updated on 26/Jun/20
Non, c'est tout à fait sa question. Mais ça ressemble beaucoup à une autre question qu'on avait posé en fs math et p'tit génie. C'est un peu complexe aussi. il suffit d'inclure sinus.
Commented by 4635 last updated on 26/Jun/20
ist the very good
$${ist}\:{the}\:{very}\:{good} \\ $$
Commented by Ar Brandon last updated on 26/Jun/20
ouais Takou
Commented by Rasheed.Sindhi last updated on 26/Jun/20
French?
$${French}? \\ $$
Commented by Ar Brandon last updated on 26/Jun/20
�� Do you feel offended, Sir ?
Commented by Rasheed.Sindhi last updated on 26/Jun/20
No sir no. Just for knowledge.  Many languages are written  in roman script.I only guess.
$${No}\:{sir}\:{no}.\:{Just}\:{for}\:{knowledge}. \\ $$$${Many}\:{languages}\:{are}\:{written} \\ $$$${in}\:{roman}\:{script}.{I}\:{only}\:{guess}. \\ $$
Commented by Rasheed.Sindhi last updated on 26/Jun/20
������
Commented by Ar Brandon last updated on 26/Jun/20
Actually I invited some of my classmates to join the forum and they're mostly French-speakers trying to get adapted to English-Language.������ No worries I hope.
Commented by Rasheed.Sindhi last updated on 26/Jun/20
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