Question Number 100528 by bemath last updated on 27/Jun/20
Commented by bemath last updated on 27/Jun/20
$$\mathrm{find}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{area}\:\mathrm{region} \\ $$
Commented by Dwaipayan Shikari last updated on 27/Jun/20
$$\mathrm{2}\left(\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{9}×\mathrm{18}\right)−\mathrm{2}×\mathrm{27}=\mathrm{108cm}^{\mathrm{2}} \\ $$
Answered by bramlex last updated on 27/Jun/20
Commented by bramlex last updated on 27/Jun/20
$$\frac{{BF}}{\mathrm{9}}\:=\:\frac{\mathrm{6}}{\mathrm{9}}\:\Rightarrow{BF}\:=\:\mathrm{6}\:{cm} \\ $$$${shaded}\:{area}\:=\:\mathrm{18}^{\mathrm{2}} −\mathrm{27}−\mathrm{2}\left(\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{6}×\mathrm{18}\right)−\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{9}×\mathrm{18} \\ $$$$=\:\mathrm{324}−\mathrm{27}−\mathrm{108}−\mathrm{81}\:=\:\mathrm{108}\:{cm}^{\mathrm{2}} \\ $$
Commented by bemath last updated on 27/Jun/20
$$\mathrm{yes} \\ $$