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Question-101767




Question Number 101767 by 175mohamed last updated on 04/Jul/20
Commented by mr W last updated on 04/Jul/20
a CD can cover a wall area of  2×(D/2)×((√3)/2)×D=(((√3)D^2 )/2)  number of CDs needed to cover  6m×4m wall area:  ((6×4 m^2 )/((((√3)×0.12^2 )/2)m^2 ))≈1425
aCDcancoverawallareaof2×D2×32×D=3D22numberofCDsneededtocover6m×4mwallarea:6×4m23×0.1222m21425
Commented by mr W last updated on 04/Jul/20

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