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Question-101794




Question Number 101794 by 175mohamed last updated on 04/Jul/20
Answered by mahdi last updated on 04/Jul/20
0<...<(1/5)<(1/4)<(1/3)         (2/3)<(3/4)<(4/5)<...<1  ⇒(0,1)
$$\mathrm{0}<…<\frac{\mathrm{1}}{\mathrm{5}}<\frac{\mathrm{1}}{\mathrm{4}}<\frac{\mathrm{1}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\frac{\mathrm{2}}{\mathrm{3}}<\frac{\mathrm{3}}{\mathrm{4}}<\frac{\mathrm{4}}{\mathrm{5}}<…<\mathrm{1} \\ $$$$\Rightarrow\left(\mathrm{0},\mathrm{1}\right) \\ $$

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