Question Number 102940 by Jamshidbek2311 last updated on 11/Jul/20
Commented by prakash jain last updated on 11/Jul/20
$${y}^{{y}} =\mathrm{3}^{−\sqrt{\mathrm{48}}} \\ $$$${y}\mathrm{ln}\:{y}=−\mathrm{4}\sqrt{\mathrm{3}}\mathrm{ln}\:\mathrm{3}<−\frac{\mathrm{1}}{{e}} \\ $$$$\mathrm{no}\:\mathrm{real}\:\mathrm{solutions}. \\ $$