Question Number 103448 by aurpeyz last updated on 15/Jul/20
Answered by Worm_Tail last updated on 15/Jul/20
$${u}_{{x}} =\mathrm{30}{cos}\mathrm{40}=\mathrm{22}.\mathrm{981}{m}.{s}^{−\mathrm{1}} \:{s}_{{x}} =\mathrm{28} \\ $$$$\:\:{s}_{{x}} ={u}_{{x}} {t}\Rightarrow{t}=\frac{\mathrm{28}}{\mathrm{22}.\mathrm{981}}=\mathrm{1}.\mathrm{2184} \\ $$$${s}_{{y}} =\left(\mathrm{30}{sin}\mathrm{40}\right)−\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{10}\right)\left(\mathrm{1}.\mathrm{2184}\right)^{\mathrm{2}} \\ $$$${s}_{{y}} =\mathrm{11}.\mathrm{8611}{m} \\ $$
Commented by aurpeyz last updated on 15/Jul/20
$$\mathrm{thanks}\:\mathrm{sir} \\ $$