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Question-103685

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Question Number 103685 by bemath last updated on 16/Jul/20
Answered by bobhans last updated on 16/Jul/20
x−(√((2−x)(3−x))) = (√(4−x)){(√(3−x))+(√(2−x))} 2x^2 −5x+6−2x(√((2−x)(3−x))) = (4−x)(5−2x)+2(√((3−x)(2−x))) 4x−7 = x(√((2−x)(3−x)))+(4−x)(√((2−x)(3−x))) 4x−7 = 4(√((2−x)(3−x))) (4x−7)^2 = 16(6−5x+x^2 ) −56x+49 = 96−80x 24x = 47 ⇒ x = ((47)/(24)) ★
x−(2−x)(3−x)=4−x{3−x+2−x}2x2−5x+6−2x(2−x)(3−x)=(4−x)(5−2x)+2(3−x)(2−x)4x−7=x(2−x)(3−x)+(4−x)(2−x)(3−x)4x−7=4(2−x)(3−x)(4x−7)2=16(6−5x+x2)−56x+49=96−80x24x=47⇒x=4724★

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