Question-104071

Question Number 104071 by DGmichael last updated on 19/Jul/20

Answered by Dwaipayan Shikari last updated on 19/Jul/20

\int 6 \sqrt{t^{2} + t + \frac{1}{4}} d t

6 \int \sqrt{{(t^{2} + \frac{1}{2})}^{2}} d t

6 \int (t^{2} + \frac{1}{2}) d t = 2 t^{3} + 3 t + C o n s t a n t

Answered by bobhans last updated on 19/Jul/20

36 t^{4} + 36 t^{2} + 9 = {(6 t^{2} + 3)}^{2} > 0, \forall t \in R

\int \sqrt{{(6 t^{2} + 3)}^{2}} d t = 2 t^{3} + 3 t + C

Commented by DGmichael last updated on 19/Jul/20

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