Question Number 104390 by I want to learn more last updated on 21/Jul/20
Answered by som(math1967) last updated on 21/Jul/20
$$\frac{\mathrm{XP}}{\mathrm{PY}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\:\frac{\mathrm{XP}}{\mathrm{XY}}=\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\frac{\mathrm{Ar}\bigtriangleup\mathrm{XPQ}}{\mathrm{Ar}\bigtriangleup\mathrm{XYZ}}=\frac{\mathrm{4}}{\mathrm{25}} \\ $$$$\frac{\mathrm{24}}{\bigtriangleup\mathrm{XYZ}}=\frac{\mathrm{4}}{\mathrm{25}} \\ $$$$\therefore\bigtriangleup\mathrm{XYZ}=\mathrm{150cm}^{\mathrm{2}} \\ $$$$\therefore\:\mathrm{Ar}.\mathrm{trap}.\mathrm{PQZY}=\mathrm{150}−\mathrm{24} \\ $$$$=\mathrm{126cm}^{\mathrm{2}} \:\mathrm{ans} \\ $$