Question-106508

Question Number 106508 by Learner-123 last updated on 05/Aug/20

Commented by JDamian last updated on 05/Aug/20

The 5 A current flows through the 30 Ohm resistor. Then the voltage at P is the sum of the voltage at that resistor (5×30=150) and the 5V from the DC voltage source.

Commented by Learner-123 last updated on 05/Aug/20

Could someone help me in finding V_(TH) ? ( I didn′t understand the sol^n !)

C o u l d s o m e o n e h e l p m e i n f i n d i n g

V_{T H} ? (I {d i d n}^{'} t u n d e r s t a n d t h e {s o l}^{n}!)

Commented by Learner-123 last updated on 05/Aug/20

sorry,it was a typo... what if I do V_(th) =20×5=100V then why it′s wrong?

s o r r y, i t w a s a t y p o \dots

w h a t i f I d o V_{t h} = 20 \times 5 = 100 V t h e n

w h y {i t}^{'} s w r o n g ?

Commented by JDamian last updated on 05/Aug/20

Where do you get that 200 from? The current from the voltage source is forced by the current source (5A). Do you know what a current source is?

W h e r e d o y o u g e t t h a t 200 f r o m ?

T h e c u r r e n t f r o m t h e v o l t a g e s o u r c e i s

f o r c e d b y t h e c u r r e n t s o u r c e (5 A) .

D o y o u k n o w w h a t a c u r r e n t s o u r c e i s ?

Commented by JDamian last updated on 05/Aug/20

Because: 1st) it is incomplete. V_(th) is the sum of the voltage of the resistor and the voltage of the current source. 2nd) those 100V you mention are actually −100V.

B e c a u s e : 1 s t) i t i s i n c o m p l e t e . V_{t h} i s t h e

s u m o f t h e v o l t a g e o f t h e r e s i s t o r a n d t h e

v o l t a g e o f t h e c u r r e n t s o u r c e . 2 n d)

t h o s e 100 V y o u m e n t i o n a r e a c t u a l l y

- 100 V .

Commented by Learner-123 last updated on 05/Aug/20

thank you sir!

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Question-106508

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