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Question-106921




Question Number 106921 by aurpeyz last updated on 07/Aug/20
Commented by aurpeyz last updated on 07/Aug/20
i didnt get the answer to the last part. pls  help
$${i}\:{didnt}\:{get}\:{the}\:{answer}\:{to}\:{the}\:{last}\:{part}.\:{pls} \\ $$$${help} \\ $$
Answered by mr W last updated on 07/Aug/20
uniform slow down means   constant acceleration  U=((8×14)/2)=56 rev  s=56×2πr=56×2π×0.3=105.6m
$${uniform}\:{slow}\:{down}\:{means}\: \\ $$$${constant}\:{acceleration} \\ $$$${U}=\frac{\mathrm{8}×\mathrm{14}}{\mathrm{2}}=\mathrm{56}\:{rev} \\ $$$${s}=\mathrm{56}×\mathrm{2}\pi{r}=\mathrm{56}×\mathrm{2}\pi×\mathrm{0}.\mathrm{3}=\mathrm{105}.\mathrm{6}{m} \\ $$
Commented by aurpeyz last updated on 07/Aug/20
thank you Sir
$${thank}\:{you}\:{Sir} \\ $$

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