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Question-106997




Question Number 106997 by Dwaipayan Shikari last updated on 08/Aug/20
Commented by mr W last updated on 08/Aug/20
mv−m×((−v)/2)=∫_0 ^T fdt=FT  ⇒F=((3mv)/(2T))
$${mv}−{m}×\frac{−{v}}{\mathrm{2}}=\int_{\mathrm{0}} ^{{T}} {fdt}={FT} \\ $$$$\Rightarrow{F}=\frac{\mathrm{3}{mv}}{\mathrm{2}{T}} \\ $$
Commented by Dwaipayan Shikari last updated on 08/Aug/20
P_f −P_i =∫Fdt  ∣−((mv)/2)−mv∣=FT  F=((3mv)/(2T))
$$\mathrm{P}_{\mathrm{f}} −\mathrm{P}_{\mathrm{i}} =\int\mathrm{Fdt} \\ $$$$\mid−\frac{\mathrm{mv}}{\mathrm{2}}−\mathrm{mv}\mid=\mathrm{FT} \\ $$$$\mathrm{F}=\frac{\mathrm{3mv}}{\mathrm{2T}} \\ $$
Commented by mr W last updated on 08/Aug/20
you are right sir! i forgot the “−” sign.
$${you}\:{are}\:{right}\:{sir}!\:{i}\:{forgot}\:{the}\:“−''\:{sign}. \\ $$

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