Question Number 107438 by lalitchand last updated on 10/Aug/20
Answered by mr W last updated on 10/Aug/20
$${x}\left(\frac{\mathrm{1}}{{n}+{p}}+\frac{\mathrm{1}}{{p}+{m}}+\frac{\mathrm{1}}{{m}+{n}}\right)=\mathrm{3}+\frac{{m}}{{n}+{p}}+\frac{{n}}{{p}+{m}}+\frac{{p}}{{m}+{n}} \\ $$$$\Rightarrow{x}=\frac{\mathrm{3}+\frac{{m}}{{n}+{p}}+\frac{{n}}{{p}+{m}}+\frac{{p}}{{m}+{n}}}{\frac{\mathrm{1}}{{n}+{p}}+\frac{\mathrm{1}}{{p}+{m}}+\frac{\mathrm{1}}{{m}+{n}}} \\ $$