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Question-108370




Question Number 108370 by mathdave last updated on 16/Aug/20
Commented by som(math1967) last updated on 16/Aug/20
∠XZY=((130)/2)=65°  ∠OZX=∠OXZ=38°  ∴∠OYZ=∠OZY=65−38=27°  ∠ZOY=180−27−27=126°
$$\angle\mathrm{XZY}=\frac{\mathrm{130}}{\mathrm{2}}=\mathrm{65}° \\ $$$$\angle\mathrm{OZX}=\angle\mathrm{OXZ}=\mathrm{38}° \\ $$$$\therefore\angle\mathrm{OYZ}=\angle\mathrm{OZY}=\mathrm{65}−\mathrm{38}=\mathrm{27}° \\ $$$$\angle\mathrm{ZOY}=\mathrm{180}−\mathrm{27}−\mathrm{27}=\mathrm{126}° \\ $$

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