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Question-108936




Question Number 108936 by mohammad17 last updated on 20/Aug/20
Commented by mohammad17 last updated on 20/Aug/20
sir can you help me (true or false)
$${sir}\:{can}\:{you}\:{help}\:{me}\:\left({true}\:{or}\:{false}\right) \\ $$
Answered by Aziztisffola last updated on 20/Aug/20
y=(5x^2 )^2 ⇒(dy/dx)=2(5x^2 )×10x=100x^3   or y=25x^4  then y′=4×25x^3 =100x^3
$$\mathrm{y}=\left(\mathrm{5x}^{\mathrm{2}} \right)^{\mathrm{2}} \Rightarrow\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{2}\left(\mathrm{5x}^{\mathrm{2}} \right)×\mathrm{10x}=\mathrm{100x}^{\mathrm{3}} \\ $$$$\mathrm{or}\:\mathrm{y}=\mathrm{25x}^{\mathrm{4}} \:\mathrm{then}\:\mathrm{y}'=\mathrm{4}×\mathrm{25x}^{\mathrm{3}} =\mathrm{100x}^{\mathrm{3}} \\ $$
Commented by mohammad17 last updated on 20/Aug/20
very thank you sir
$${very}\:{thank}\:{you}\:{sir} \\ $$

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