Question Number 108997 by 150505R last updated on 20/Aug/20
Answered by Dwaipayan Shikari last updated on 20/Aug/20
$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{sin}\left({n}^{\mathrm{2}} \pi\sqrt[{\mathrm{3}}]{\mathrm{1}+\frac{\mathrm{3}}{{n}}+\frac{\mathrm{4}}{{n}^{\mathrm{2}} }−\frac{\mathrm{5}}{{n}^{\mathrm{3}} }}\:\right) \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{sin}\left({n}^{\mathrm{2}} \pi\right)={f}\left({x}\right) \\ $$$$−\mathrm{1}\leqslant{f}\left({x}\right)\leqslant\mathrm{1} \\ $$$$ \\ $$