Question Number 111264 by bobhans last updated on 03/Sep/20
Commented by bobhans last updated on 03/Sep/20
Answered by abdomsup last updated on 03/Sep/20
$$=\mathrm{0}\:{due}\:{to}\:\mid{sin}\left(\frac{\mathrm{2}}{{x}}\right)\mid\leqslant\mathrm{1}\:{for}\:{x}\neq\mathrm{0} \\ $$