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Question-111601




Question Number 111601 by A8;15: last updated on 04/Sep/20
Answered by bemath last updated on 04/Sep/20
((7.7^(2004) +7^(2004) +1)/(7^(2004) +1)) = ((8.7^(2004) +1)/(7^(2004) +1))
$$\frac{\mathrm{7}.\mathrm{7}^{\mathrm{2004}} +\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}\:=\:\frac{\mathrm{8}.\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}} \\ $$

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