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Question-111788




Question Number 111788 by 675480065 last updated on 04/Sep/20
Answered by bemath last updated on 05/Sep/20
 a = 3 , b = 4 ; c = 4  ⇔ 3! 3! = (6)^2  = 36  ⇔ 3!+3!+4! = 6+6+24 = 36
$$\:{a}\:=\:\mathrm{3}\:,\:{b}\:=\:\mathrm{4}\:;\:{c}\:=\:\mathrm{4} \\ $$$$\Leftrightarrow\:\mathrm{3}!\:\mathrm{3}!\:=\:\left(\mathrm{6}\right)^{\mathrm{2}} \:=\:\mathrm{36} \\ $$$$\Leftrightarrow\:\mathrm{3}!+\mathrm{3}!+\mathrm{4}!\:=\:\mathrm{6}+\mathrm{6}+\mathrm{24}\:=\:\mathrm{36}\: \\ $$

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