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Question-113885




Question Number 113885 by Aina Samuel Temidayo last updated on 16/Sep/20
Answered by MJS_new last updated on 16/Sep/20
x=((ln bc)/(ln a))     y=((ln ac)/(ln b))     z=((ln ab)/(ln c))  ln a =o; ln b =p ; ln c =q  xyz=(o/p)+(o/q)+(p/o)+(p/q)+(q/o)+(q/p)+2=x+y+z+2
$${x}=\frac{\mathrm{ln}\:{bc}}{\mathrm{ln}\:{a}}\:\:\:\:\:{y}=\frac{\mathrm{ln}\:{ac}}{\mathrm{ln}\:{b}}\:\:\:\:\:{z}=\frac{\mathrm{ln}\:{ab}}{\mathrm{ln}\:{c}} \\ $$$$\mathrm{ln}\:{a}\:={o};\:\mathrm{ln}\:{b}\:={p}\:;\:\mathrm{ln}\:{c}\:={q} \\ $$$${xyz}=\frac{{o}}{{p}}+\frac{{o}}{{q}}+\frac{{p}}{{o}}+\frac{{p}}{{q}}+\frac{{q}}{{o}}+\frac{{q}}{{p}}+\mathrm{2}={x}+{y}+{z}+\mathrm{2} \\ $$

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