Question-113886

Question Number 113886 by Aina Samuel Temidayo last updated on 16/Sep/20

Answered by MJS_new last updated on 16/Sep/20

(a)

Commented by Aina Samuel Temidayo last updated on 16/Sep/20

Solution please ?

Commented by MJS_new last updated on 16/Sep/20

lol \dots just use your brain

Answered by Rasheed.Sindhi last updated on 16/Sep/20

a^{x} = {(x + y + z)}^{y}, a^{y} = {(x + y + z)}^{z}, a^{z} = {(x + y + z)}^{x}

a = {(x + y + z)}^{y / x} = {(x + y + z)}^{z / y} = {(x + y + z)}^{x / z}

\frac{y}{x} = \frac{z}{y} = \frac{x}{z} = \frac{x + y + z}{x + y + z} = 1

y = x, z = y, x = z

x = y = z = k (s a y)

a^{k} = {(k + k + k)}^{k}

a = 3 k

k = a / 3 = x = y = z

Answered by Rasheed.Sindhi last updated on 17/Sep/20

M u l t i p l y i n g a l l t h e t h r e e

a^{x + y + z} = {(x + y + z)}^{x + y + z}

a = x + y + z \dots \dots \dots \dots \dots \dots . A

a^{x} = a^{y}, a^{y} = a^{z}, a^{z} = a^{x}

\frac{a^{x}}{a^{y}} = \frac{a^{y}}{a^{z}} = \frac{a^{z}}{a^{x}} = 1

a^{x - y} = a^{y - z} = a^{z - x} = a^{0}

x - y = y - z = z - x = 0

x = y = z = k (s a y)

I n A

a = k + k + k = 3 k \Rightarrow k = a / 3

k = x = y = z = a / 3