Question Number 116611 by gaminghanzo12 last updated on 05/Oct/20
Commented by Dwaipayan Shikari last updated on 05/Oct/20
$$\mathrm{Q}\:\mathrm{116516} \\ $$
Answered by TANMAY PANACEA last updated on 05/Oct/20
$$\frac{{a}}{{b}+{c}}+\mathrm{1}+\frac{{b}}{{a}+{c}}+\mathrm{1}+\frac{{c}}{{a}+{b}}+\mathrm{1}−\mathrm{3} \\ $$$$\left({a}+{b}+{c}\right)\left(\frac{\mathrm{1}}{{b}+{c}}+\frac{\mathrm{1}}{{a}+{c}}+\frac{\mathrm{1}}{{a}+{b}}\right)−\mathrm{3} \\ $$$$\mathrm{7}×\frac{\mathrm{7}}{\mathrm{10}}−\mathrm{3}=\frac{\mathrm{49}−\mathrm{30}}{\mathrm{10}}=\frac{\mathrm{19}}{\mathrm{10}} \\ $$