Menu Close

Question-116641




Question Number 116641 by nguyenthanh last updated on 05/Oct/20
Answered by TANMAY PANACEA last updated on 05/Oct/20
A=B=C=60^o   sin30^o ×sin30^o ×sin30^o =(1/8)  cos60^o ×cos60^o ×cos60^o =(1/8)
$${A}={B}={C}=\mathrm{60}^{{o}} \\ $$$${sin}\mathrm{30}^{{o}} ×{sin}\mathrm{30}^{{o}} ×{sin}\mathrm{30}^{{o}} =\frac{\mathrm{1}}{\mathrm{8}} \\ $$$${cos}\mathrm{60}^{{o}} ×{cos}\mathrm{60}^{{o}} ×{cos}\mathrm{60}^{{o}} =\frac{\mathrm{1}}{\mathrm{8}} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *