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Question-116658




Question Number 116658 by zakirullah last updated on 05/Oct/20
Commented by Rasheed.Sindhi last updated on 08/Oct/20
                AnOther Way ↶↑_(↓) ↷  12=2^2 .3  The smallest perfect square   divisible by 12 : 2^2 .3.3=36  16=2^4   The smallest perfect square   divisible by 16 : 2^4 =16  20=2^2 .5  The smallest perfect square   divisible by 20 : 2^2 .5.5=100  24=2^3 .3  The smallest perfect square   divisible by 24 : 2^3 .3.2.3=144  The smallest perfect square  number which is divisible  by 12,16,20 & 24:  LCM(36,16,100,144)=3600
AnOtherWay12=22.3Thesmallestperfectsquaredivisibleby12:22.3.3=3616=24Thesmallestperfectsquaredivisibleby16:24=1620=22.5Thesmallestperfectsquaredivisibleby20:22.5.5=10024=23.3Thesmallestperfectsquaredivisibleby24:23.3.2.3=144Thesmallestperfectsquarenumberwhichisdivisibleby12,16,20&24:LCM(36,16,100,144)=3600
Commented by zakirullah last updated on 08/Oct/20
thank so much sir
thanksomuchsir
Answered by mr W last updated on 05/Oct/20
12=2^2 ×3  16=2^4   20=2^2 ×5  24=2^3 ×3  ⇒2^4 ×3^2 ×5^2 =3600
12=22×316=2420=22×524=23×324×32×52=3600
Commented by zakirullah last updated on 05/Oct/20
thanks alot
thanksalot
Commented by zakirullah last updated on 05/Oct/20
   sir how 5^2  comes
sirhow52comes
Commented by JDamian last updated on 05/Oct/20
it is on purpose. Otherwise the number wouldn't be a perfect squared. In fact, all the primes of the number must be present as an even power.
Answered by $@y@m last updated on 05/Oct/20
12= 2×2×3  16= 2×2×2×2  20=2×2×5  24=2×2×2×3  All except 5  have pair.  Therefore required no.is  2×2×2×2×3×3×5×5=3600
12=2×2×316=2×2×2×220=2×2×524=2×2×2×3Allexcept5havepair.Thereforerequiredno.is2×2×2×2×3×3×5×5=3600
Commented by zakirullah last updated on 05/Oct/20
sir ans is 3600
siransis3600
Commented by zakirullah last updated on 05/Oct/20
thanks
thanks

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