Question Number 117800 by Khalmohmmad last updated on 13/Oct/20
Answered by mr W last updated on 13/Oct/20
$$\mathrm{log}\:\mathrm{2}=\mathrm{log}\:\frac{\mathrm{6}}{\mathrm{3}}=\mathrm{log}\:\mathrm{6}−\mathrm{log}\:\mathrm{3}={a}−{b} \\ $$$$\mathrm{log}\:\mathrm{25}=\mathrm{log}\:\left(\frac{\mathrm{10}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\mathrm{log}\:\mathrm{10}−\mathrm{log}\:\mathrm{2}\right) \\ $$$$=\mathrm{2}\left(\mathrm{1}−{a}+{b}\right) \\ $$