Question Number 118209 by bemath last updated on 16/Oct/20
Answered by MJS_new last updated on 16/Oct/20
$${AB}={y} \\ $$$$\left(\mathrm{1}\right)\:\:\:\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{20}^{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:\:\:\:\:\left({x}−\mathrm{7}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{15}^{\mathrm{2}} \\ $$$$\left(\mathrm{1}\right)−\left(\mathrm{2}\right) \\ $$$$\mathrm{14}{x}−\mathrm{49}=\mathrm{175}\:\Rightarrow\:{x}=\mathrm{16} \\ $$$$\left(\Rightarrow\:{y}=\mathrm{12}\right) \\ $$