Question Number 119298 by zakirullah last updated on 23/Oct/20
Answered by bemath last updated on 23/Oct/20
![(1) let the point we requires is T such that CT : TD = 2 : 5 ⇒t^→ = ((5c^→ +2d^→ )/(5+2)) t^→ = (1/7)[ (0,25,0)+(8,2,0) ] t^→ = (((8,27,0))/7) = ((8/7),((27)/7),0)](https://www.tinkutara.com/question/Q119301.png)
$$\left(\mathrm{1}\right)\:{let}\:{the}\:{point}\:{we}\:{requires}\:{is}\:{T}\:{such}\:{that} \\ $$$${CT}\::\:{TD}\:=\:\mathrm{2}\::\:\mathrm{5}\:\Rightarrow\overset{\rightarrow} {{t}}\:=\:\frac{\mathrm{5}\overset{\rightarrow} {{c}}+\mathrm{2}\overset{\rightarrow} {{d}}}{\mathrm{5}+\mathrm{2}} \\ $$$$\overset{\rightarrow} {{t}}=\:\frac{\mathrm{1}}{\mathrm{7}}\left[\:\left(\mathrm{0},\mathrm{25},\mathrm{0}\right)+\left(\mathrm{8},\mathrm{2},\mathrm{0}\right)\:\right] \\ $$$$\overset{\rightarrow} {{t}}\:=\:\frac{\left(\mathrm{8},\mathrm{27},\mathrm{0}\right)}{\mathrm{7}}\:=\:\left(\frac{\mathrm{8}}{\mathrm{7}},\frac{\mathrm{27}}{\mathrm{7}},\mathrm{0}\right) \\ $$
Commented by zakirullah last updated on 23/Oct/20
$${thanks} \\ $$