Question Number 119527 by joki last updated on 25/Oct/20
Commented by benjo_mathlover last updated on 25/Oct/20
$$\left({a}\right){P}\left({male}/{secondary}\:{education}\right)\:=\:\frac{{P}\left({M}\cap{E}\right)}{{P}\left({E}\right)} \\ $$$$\:=\:\frac{\mathrm{28}}{\mathrm{28}+\mathrm{50}}\:=\:\frac{\mathrm{28}}{\mathrm{78}}\:=\:\frac{\mathrm{14}}{\mathrm{39}}\:. \\ $$
Commented by joki last updated on 25/Oct/20
$${b}? \\ $$
Answered by benjo_mathlover last updated on 25/Oct/20
$$\left({b}\right){P}\left({A}/{B}\right)\:=\:\frac{{P}\left({A}\cap{B}\right)}{{P}\left({B}\right)}=\:\frac{\mathrm{45}+\mathrm{50}}{\mathrm{45}+\mathrm{50}+\mathrm{17}} \\ $$$${A}\::\:{does}\:{not}\:{have}\:{college}\:{degree} \\ $$$${B}\::\:{female} \\ $$
Commented by joki last updated on 25/Oct/20
$${number}\:\mathrm{2}.\mathrm{98}\:{sir},{i}\:{dont}\:{understand}.\:{thanks}\:{sir} \\ $$
Answered by benjo_mathlover last updated on 25/Oct/20
$${P}\left({W}\right)\:=\:{P}\left({A}\cap{B}\cap{C}\cap{D}\right)+{P}\left({A}\cap{B}\cap{C}^{{c}} \cap{D}\right) \\ $$$$\:\:\:\:\:\:\:+\:{P}\left({A}\cap{B}^{{c}} \cap{C}\cap{D}\right) \\ $$