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Question-120194




Question Number 120194 by huotpat last updated on 30/Oct/20
Answered by MJS_new last updated on 30/Oct/20
let y=px∧z=qx with p, q ∈R  lim_(x→0)  ((pqx^3 )/((p^2 +q^2 +1)x^2 )) =lim_(x→0)  ((pqx)/(p^2 +q^2 +1)) =0
$$\mathrm{let}\:{y}={px}\wedge{z}={qx}\:\mathrm{with}\:{p},\:{q}\:\in\mathbb{R} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{pqx}^{\mathrm{3}} }{\left({p}^{\mathrm{2}} +{q}^{\mathrm{2}} +\mathrm{1}\right){x}^{\mathrm{2}} }\:=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{pqx}}{{p}^{\mathrm{2}} +{q}^{\mathrm{2}} +\mathrm{1}}\:=\mathrm{0} \\ $$

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