Question Number 120237 by aurpeyz last updated on 30/Oct/20
Commented by Dwaipayan Shikari last updated on 30/Oct/20
$$\bigtriangleup{P}=\mid{m}.{v}_{\mathrm{1}} −{mv}_{\mathrm{2}} \mid={m}\sqrt{\mathrm{2}{g}}\left(\mathrm{2}+\sqrt{\mathrm{3}}\right) \\ $$$${v}_{\mathrm{1}} =\sqrt{\mathrm{2}{g}.\mathrm{4}} \\ $$$${v}_{\mathrm{2}} =\sqrt{\mathrm{2}{g}.\mathrm{3}} \\ $$$$\frac{\bigtriangleup{P}}{\bigtriangleup{t}}={F}_{{ext}} =\frac{{m}\sqrt{\mathrm{2}{g}}\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)}{\mathrm{0}.\mathrm{01}} \\ $$$${a}=\frac{{F}_{{ext}} }{{m}}=\mathrm{100}\sqrt{\mathrm{2}{g}}\:\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)\:\:\left({upward}\right) \\ $$